Given two binary strings, return their sum (also a binary string).
The input strings are both non-empty and contains only characters 1
or 0
.
Example 1:
Input: a = "11", b = "1"
Output: "100"
Example 2:
Input: a = "1010", b = "1011"
Output: "10101"
Tags: Math, String
题意是给你两个二进制串,求其和的二进制串。我们就按照小学算数那么来做,用 carry
表示进位,从后往前算,依次往前,每算出一位就插入到最前面即可,直到把两个二进制串都遍历完即可。
class Solution {
public String addBinary(String a, String b) {
StringBuilder sb = new StringBuilder();
int carry = 0, p1 = a.length() - 1, p2 = b.length() - 1;
while (p1 >= 0 && p2 >= 0) {
carry += a.charAt(p1--) - '0';
carry += b.charAt(p2--) - '0';
sb.insert(0, (char) (carry % 2 + '0'));
carry >>= 1;
}
while (p1 >= 0) {
carry += a.charAt(p1--) - '0';
sb.insert(0, (char) (carry % 2 + '0'));
carry >>= 1;
}
while (p2 >= 0) {
carry += b.charAt(p2--) - '0';
sb.insert(0, (char) (carry % 2 + '0'));
carry >>= 1;
}
if (carry == 1) {
sb.insert(0, '1');
}
return sb.toString();
}
}
如果你同我一样热爱数据结构、算法、LeetCode,可以关注我 GitHub 上的 LeetCode 题解:awesome-java-leetcode