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solution.java
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solution.java
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// Never seen it before = insert and set to 1 to indiciate we've now seen it
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
public class solution {
// Complete the sherlockAndAnagrams function below.
static int sherlockAndAnagrams(String s) {
HashMap<String, Integer> map = new HashMap<String, Integer>();
// total anagrams
int totalCount = 0;
for (int i = 0; i < s.length(); i++) {
for (int j = i + 1; j <= s.length(); j++) {
String currentSubString = s.substring(i, j);
// Sort all strings E.g. ab & ba both == ab
char[] chars = currentSubString.toCharArray();
Arrays.sort(chars);
currentSubString = String.valueOf(chars);
// If sorted substring has been seen before
if (map.containsKey(currentSubString)) {
// Check how many times we've seen it and add that amount to the count
int value = map.get(currentSubString);
totalCount = totalCount + value;
// Increament the times we've seen the string
map.put(currentSubString, value + 1);
} else {
// if we are seeing it for the first time set it's value as 1
map.put(currentSubString, 1);
}
}
}
return totalCount;
}
private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) throws IOException {
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
int q = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
for (int qItr = 0; qItr < q; qItr++) {
String s = scanner.nextLine();
int result = sherlockAndAnagrams(s);
bufferedWriter.write(String.valueOf(result));
bufferedWriter.newLine();
}
bufferedWriter.close();
scanner.close();
}
}