You signed in with another tab or window. Reload to refresh your session.You signed out in another tab or window. Reload to refresh your session.You switched accounts on another tab or window. Reload to refresh your session.Dismiss alert
df =DataFrame(a = [1, 2, missing], b = [4, 5, 6])
@subset(df, :a.==1; view =true)
# return a SubDataFrame@subset(df, :a.==1; skipmissing =false)
# throw an error as there is a missing value in the condition@subset(df, :a.==1, :b.==4; view =true)
# return a DataFrame rather than a SubDataFrame!!!@subset(df, :a.==1, :b.==4; skipmissing =false)
# return a DataFrame! No error was thrown.
See the example below:
Version info: Julia 1.10
[a93c6f00] DataFrames v1.6.1
[1313f7d8] DataFramesMeta v0.15.2
The text was updated successfully, but these errors were encountered: