Extract Julia code from SymPy expression?

[dpsanders]

Is there a way of extracting the Julia code from a SymPy expression, i.e. what lambdify does but returning the Julia source code for the body of the function, instead of the anonymous function itself?

[mzaffalon]

Is what you want fn defined at https://github.com/JuliaPy/SymPy.jl/blob/master/src/lambdify.jl#L150? The following line returns the anonymous function.

[dpsanders]

Thanks it looks like sympy_meth(:julia_code, s) is actually what I was looking for.

[asmeurer]

SymPy also has a built in Julia code generator https://github.com/sympy/sympy/blob/master/sympy/printing/julia.py

[ccmejia]

SymPy also has a built in Julia code generator https://github.com/sympy/sympy/blob/master/sympy/printing/julia.py

I’ve been trying whit julia_code generator but it seems that I must should do something before:
UndefVarError: julia_code not defined
:(

[jverzani]

This is in the lambdify code defn:

body = Meta.parse(sympy.julia_code(ex))

We don't actually use it unless asked, as there had been issues with a few things.

If that isn't what you are lookiing for, please re-open.