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solution.java
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solution.java
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import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
public class Solution {
// Complete the surfaceArea function below.
static int surfaceArea(int[][] A) {
int n=A.length, m = A[0].length;
//area of upper and lower surfaces(sides) will be its projection i.e. n*m
int area = 2*n*m;
//to access all the 4 neighbors
int[][] c = {{-1,0},
{0,-1},
{1,0},
{0,1}};
//now we are left with 4 sides
//let's go one by one through each coordinate
for(int i=0;i<n;i++){
for(int j=0;j<m;j++){
for(int[] t: c){
try{
//accessing the height of the side neighbor
int side = A[i+t[0]][j+t[1]];
//if it is less than the height of the current cell then
//the surface area of this side is their height difference
if(A[i][j]>side) area+=A[i][j]-side;
}
catch(ArrayIndexOutOfBoundsException e){
//if this exception is raised that means this is a extreme cell
//and hence the area is equal to its height
area+= A[i][j];
}
}
}
}
return area;
}
private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) throws IOException {
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
String[] HW = scanner.nextLine().split(" ");
int H = Integer.parseInt(HW[0]);
int W = Integer.parseInt(HW[1]);
int[][] A = new int[H][W];
for (int i = 0; i < H; i++) {
String[] ARowItems = scanner.nextLine().split(" ");
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
for (int j = 0; j < W; j++) {
int AItem = Integer.parseInt(ARowItems[j]);
A[i][j] = AItem;
}
}
int result = surfaceArea(A);
bufferedWriter.write(String.valueOf(result));
bufferedWriter.newLine();
bufferedWriter.close();
scanner.close();
}
}