We read every piece of feedback, and take your input very seriously.
To see all available qualifiers, see our documentation.
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
with_suffix()
I love how yarl follows the pathlib.Path syntax, so was a bit disappointed to not have a with_suffix() method when I needed it. Could it be added?
Similar to pathlib, with_suffix() should take a URL to a file, like:
url = yarl.URL("https://a.b.com/index.html")
and change it to:
url.with_suffix(".md")
-> https://a.b.com/index.md
with_name() works as a workaround, but it's sometimes cumbersome to fish out the name first, and do string ops on it before adding it back to the URL.
with_name()
No response
The text was updated successfully, but these errors were encountered:
The request makes sense. Please feel free to prepare a patch. I would say that .suffix attribute should be supported if .with_suffix() is added.
.suffix
.with_suffix()
Sorry, something went wrong.
with_suffix
Successfully merging a pull request may close this issue.
Is your feature request related to a problem?
I love how yarl follows the pathlib.Path syntax, so was a bit disappointed to not have a
with_suffix()
method when I needed it. Could it be added?Describe the solution you'd like
Similar to pathlib,
with_suffix()
should take a URL to a file, like:url = yarl.URL("https://a.b.com/index.html")
and change it to:
url.with_suffix(".md")
-> https://a.b.com/index.md
Describe alternatives you've considered
with_name()
works as a workaround, but it's sometimes cumbersome to fish out the name first, and do string ops on it before adding it back to the URL.Additional context
No response
Code of Conduct
The text was updated successfully, but these errors were encountered: