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1249. Minimum Remove to Make Valid Parentheses.java
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1249. Minimum Remove to Make Valid Parentheses.java
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M
tags: String, Stack
time: O(n)
space: O(n)
#### Stack
- Goal: remove extra '(' or ')' so it is valid.
- Forward thinking: use stack to track '(' and ')', then keep appending partial string to output
- Backward thinking: use stack to filter out false indexes, and remove them in the end
```
/*
Given a string s of '(' , ')' and lowercase English characters.
Your task is to remove the minimum number of parentheses ( '(' or ')', in any positions ) so that the resulting parentheses string is valid and return any valid string.
Formally, a parentheses string is valid if and only if:
It is the empty string, contains only lowercase characters, or
It can be written as AB (A concatenated with B), where A and B are valid strings, or
It can be written as (A), where A is a valid string.
Example 1:
Input: s = "lee(t(c)o)de)"
Output: "lee(t(c)o)de"
Explanation: "lee(t(co)de)" , "lee(t(c)ode)" would also be accepted.
Example 2:
Input: s = "a)b(c)d"
Output: "ab(c)d"
Example 3:
Input: s = "))(("
Output: ""
Explanation: An empty string is also valid.
Example 4:
Input: s = "(a(b(c)d)"
Output: "a(b(c)d)"
Constraints:
1 <= s.length <= 10^5
s[i] is one of '(' , ')' and lowercase English letters.
*/
/*
Goal: remove extra ( or ) so it is valid.
Forward thinking: use stack to track ( and ), then keep appending partial string to final result
Backward thinking: use stack to filter out false indexes, and remove them in the end
*/
class Solution {
public String minRemoveToMakeValid(String s) {
Set<Integer> set = new HashSet<>();
Stack<Integer> stack = new Stack<>();
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
if (c == '(') stack.push(i);
if (c == ')') {
if (!stack.isEmpty()) stack.pop();
else set.add(i); // given ')' but missing '(', record ')' as false index
}
}
// remaining false indexes of '('
while (!stack.isEmpty()) set.add(stack.pop());
StringBuffer sb = new StringBuffer();
for (int i = 0; i < s.length(); i++) {
if (!set.contains(i)) sb.append(s.charAt(i));
}
return sb.toString();
}
}
```