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FourSum.java
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FourSum.java
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import java.util.*;
/**
* Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target?
* Find all unique quadruplets in the array which gives the sum of target.
* <p>
* Note: The solution set must not contain duplicate quadruplets.
* <p>
* For example, given array S = [1, 0, -1, 0, -2, 2], and target = 0.
* <p>
* A solution set is:
* [
* [-1, 0, 0, 1],
* [-2, -1, 1, 2],
* [-2, 0, 0, 2]
* ]
* <p>
* Accepted.
*/
public class FourSum {
// Time Limit Exceeded.
/*public List<List<Integer>> fourSum(int[] nums, int target) {
Set<List<Integer>> set = new HashSet<>();
Arrays.sort(nums);
for (int i = 0; i < nums.length - 3; i++) {
for (int j = i + 1; j < nums.length - 2; j++) {
for (int k = j + 1; k < nums.length - 1; k++) {
for (int m = k + 1; m < nums.length; m++) {
int sum = nums[i] + nums[j] + nums[k] + nums[m];
if (sum > target) {
continue;
}
if (sum == target) {
List<Integer> tmp = new ArrayList<>(4);
tmp.add(nums[i]);
tmp.add(nums[j]);
tmp.add(nums[k]);
tmp.add(nums[m]);
set.add(tmp);
}
}
}
}
}
return new ArrayList<>(set);
}*/
public List<List<Integer>> fourSum(int[] nums, int target) {
List<List<Integer>> results = new ArrayList<>();
Arrays.sort(nums);
for (int i = 0; i < nums.length - 3; i++) {
for (int j = i + 1; j < nums.length - 2; j++) {
int left = j + 1, right = nums.length - 1;
while (left < right) {
int sum = nums[i] + nums[j] + nums[left] + nums[right];
if (sum == target) {
List<Integer> tmp = new ArrayList<>(4);
tmp.add(nums[i]);
tmp.add(nums[j]);
tmp.add(nums[left]);
tmp.add(nums[right]);
if (!results.contains(tmp)) {
results.add(tmp);
}
left++;
right--;
} else if (sum < target) {
left++;
} else {
right--;
}
}
}
}
return results;
}
}