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Why Function.defineOperator? #4

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trusktr opened this issue Dec 22, 2019 · 1 comment
Open

Why Function.defineOperator? #4

trusktr opened this issue Dec 22, 2019 · 1 comment

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@trusktr
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trusktr commented Dec 22, 2019

I like the idea of operator overloads, but what does it have to do with Function? Why is it a static method on Function? Why not global.defineOperator(), or a new Meta object with the method, or something?

@kevinbarabash
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I was modelling it after Object.defineProperty(). I really could've been anything.

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