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+= ternary #446

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laurentlb opened this issue Aug 24, 2024 · 0 comments
Open

+= ternary #446

laurentlb opened this issue Aug 24, 2024 · 0 comments

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@laurentlb
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Input

void main() {
  if (x) {
    y += 1.;
  } else {
    y += 2.;
  }
}

Current output:

void main(){y=x?y+1.:y+2.;}

I would expect the += operator to be preserved.

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