Expression inside lt triggers Stack Overflow Error

[MarkCampbell90]

Aim

I want to executing following (already minimized) program:

pub fn main(input : Field) -> pub bool {
    input.lt((((((((((((((((((1))))))))))))))))))
}

If the expression is moved to a variable everything is fine:

pub fn main(input : Field) -> pub bool {
    let var : Field = (((((((((((((((((1)))))))))))))))));
    nput.lt(var)
}

I would be interested to know:

• Is this a known limitation of the lt function?
• Are there other limitations like this?

Expected Behavior

I expected expressions to behave similar everywhere in code, no matter if present in an assignment or as an argument to lt( ... ). Additionally, the expression depth limit seems very small in this particular case.

Bug

thread '<unknown>' has overflowed its stack
fatal runtime error: stack overflow
Aborted

To Reproduce

1. create a noir / nargo project with the given content
2. nargo execute

Workaround

None

Workaround Description

Assigning the expression to a variable before passing it to the lt function as argument.

Additional Context

No response

Project Impact

None

Blocker Context

No response

Nargo Version

nargo version = 0.34.0 noirc version = 0.34.0+e3cdebe515e4dc4ee6e16e01bd8af25135939798 (git version hash: e3cdebe, is dirty: false)

NoirJS Version

No response

Proving Backend Tooling & Version

No response

Would you like to submit a PR for this Issue?

None

Support Needs

No response