You signed in with another tab or window. Reload to refresh your session.You signed out in another tab or window. Reload to refresh your session.You switched accounts on another tab or window. Reload to refresh your session.Dismiss alert
Question:
Mel uses a 900-watt air conditioner for 8 hours a day. This means that each hour the AC uses 900 watts of energy. If he reduces the time he uses the air conditioner by 5 hours a day, how many kilowatts of electric energy will he save in 30 days?
Answer:
An air conditioner uses 900 x 8 = <<9008=7200>>7200 watts for 8 hours a day.\nAn air conditioner uses 900 x 5 = <<9005=4500>>4500 watts for 5 hours a day.\nSo, Mel saves 7200 - 4500 = <<7200-4500=2700>>2700 watts per day.\nThat is 2700/1000 = <<2700/1000=2.7>>2.7 kilowatts per day since 1 kilowatt is equal to 1000 watts.\nHence, in 30 days he will have 2.7 x 30 = <<2.7*30=81>>81 kilowatts of electric energy saved.\n#### 81
The answer is incorrectly returning the energy he is USING after reducing by 5 hours per day (i.e. 3 hours), instead of the energy he is SAVING.
0.9 kW per hour * 3 hours = 2.7 kWh * 30 days = 81 kWh
The correct answer should be the 5 hours a day he is saving.
0.9 kW per hours * 5 hours = 4.5 kWh * 30 days = 135 kWh
The text was updated successfully, but these errors were encountered:
Question:
Mel uses a 900-watt air conditioner for 8 hours a day. This means that each hour the AC uses 900 watts of energy. If he reduces the time he uses the air conditioner by 5 hours a day, how many kilowatts of electric energy will he save in 30 days?
Answer:
An air conditioner uses 900 x 8 = <<9008=7200>>7200 watts for 8 hours a day.\nAn air conditioner uses 900 x 5 = <<9005=4500>>4500 watts for 5 hours a day.\nSo, Mel saves 7200 - 4500 = <<7200-4500=2700>>2700 watts per day.\nThat is 2700/1000 = <<2700/1000=2.7>>2.7 kilowatts per day since 1 kilowatt is equal to 1000 watts.\nHence, in 30 days he will have 2.7 x 30 = <<2.7*30=81>>81 kilowatts of electric energy saved.\n#### 81
The answer is incorrectly returning the energy he is USING after reducing by 5 hours per day (i.e. 3 hours), instead of the energy he is SAVING.
0.9 kW per hour * 3 hours = 2.7 kWh * 30 days = 81 kWh
The correct answer should be the 5 hours a day he is saving.
0.9 kW per hours * 5 hours = 4.5 kWh * 30 days = 135 kWh
The text was updated successfully, but these errors were encountered: