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_42.java
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_42.java
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package com.fishercoder.solutions;
/**
* 42. Trapping Rain Water
* Given n non-negative integers representing an elevation map where the width of each bar is 1,
* compute how much water it is able to trap after raining.
For example,
Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6.
The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1].
In this case, 6 units of rain water (blue section) are being trapped.
*/
public class _42 {
public static class Solution1 {
/**
* O(n) time and O(1) space, awesome!
*
* 1. first scan to find the max height index
* 2. then scan from left up to max index and find all the water units up to the max height
* 3. then scan from right down to max index and find all the water units down to the max height
* 4. return the sum of those above two
*
* reference: https://discuss.leetcode.com/topic/22976/my-accepted-java-solution
*/
public int trap(int[] height) {
if (height == null || height.length <= 2) {
return 0;
}
int max = height[0];
int maxIndex = 0;
for (int i = 0; i < height.length; i++) {
if (height[i] > max) {
max = height[i];
maxIndex = i;
}
}
int water = 0;
int leftMax = height[0];
for (int i = 0; i < maxIndex; i++) {
if (height[i] > leftMax) {
leftMax = height[i];
} else {
water += leftMax - height[i];
}
}
int rightMax = height[height.length - 1];
for (int i = height.length - 1; i > maxIndex; i--) {
if (height[i] > rightMax) {
rightMax = height[i];
} else {
water += rightMax - height[i];
}
}
return water;
}
}
}