Laneia #39
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CheezItMan
reviewed
Oct 18, 2019
| # insert the new node at the beginning of the linked list | ||
| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def add_first(value) |
| # returns true if found, false otherwise | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def search(value) |
| # returns the data value and not the node | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def find_max |
| # method to return the min value in the linked list | ||
| # returns the data value and not the node | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) |
There was a problem hiding this comment.
I think you meant space complexity O(1)
| # returns the data value and not the node | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def find_min |
| # assume indexing starts at 0 while counting to n | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def find_nth_from_end(n) |
| # returns true if a cycle is found, false otherwise. | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def has_cycle |
| # method that inserts a given value as a new last node in the linked list | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def add_last(value) |
| # returns nil if the linked list is empty | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def get_last |
| # list is sorted in ascending order | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def insert_ascending(value) |
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