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We currently have expr.dt.year() and expr.dt.day() but not expr.dt.hour() which returns an int of that hour of the day.
expr.dt.year()
expr.dt.day()
expr.dt.hour()
The text was updated successfully, but these errors were encountered:
[FEAT] 1606 - Adding hour expression in date util (#1637)
55a95ab
Adds `dt_hour()` Expression to fetch hour of the current day in a column. Based on, #1606
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We currently have
expr.dt.year()
andexpr.dt.day()
but notexpr.dt.hour()
which returns an int of that hour of the day.The text was updated successfully, but these errors were encountered: