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Avoid cumbersome formatter workaround #6573

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Jun 4, 2024
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19 changes: 4 additions & 15 deletions packages/flutter_markdown/test/image_test_mocks.dart
Original file line number Diff line number Diff line change
Expand Up @@ -3,7 +3,6 @@
// found in the LICENSE file.

import 'dart:async';
import 'dart:convert';
import 'dart:io';

import 'package:mockito/mockito.dart';
Expand Down Expand Up @@ -69,25 +68,15 @@ MockHttpClient createMockImageHttpClient(SecurityContext? _) {
return client;
}

// This string represents the hexidecial bytes of a transparent image. A
// string is used to make the visual representation of the data compact. A
// List<int> of the same data requires over 60 lines in a source file with
// each element in the array on a single line.
const String _imageBytesAsString = '''
// A list of integers that can be consumed as image data in a stream.
final List<int> _transparentImage = <int>[
// Image bytes.
0x89, 0x50, 0x4E, 0x47, 0x0D, 0x0A, 0x1A, 0x0A, 0x00, 0x00, 0x00, 0x0D, 0x49,
0x48, 0x44, 0x52, 0x00, 0x00, 0x00, 0x01, 0x00, 0x00, 0x00, 0x01, 0x08, 0x06,
0x00, 0x00, 0x00, 0x1F, 0x15, 0xC4, 0x89, 0x00, 0x00, 0x00, 0x0A, 0x49, 0x44,
0x41, 0x54, 0x78, 0x9C, 0x63, 0x00, 0x01, 0x00, 0x00, 0x05, 0x00, 0x01, 0x0D,
0x0A, 0x2D, 0xB4, 0x00, 0x00, 0x00, 0x00, 0x49, 0x45, 0x4E, 0x44, 0xAE,
''';

// Convert the string representing the hexidecimal bytes in the image into
// a list of integers that can be consumed as image data in a stream.
final List<int> _transparentImage = const LineSplitter()
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Contributor Author

@lrhn lrhn Apr 19, 2024

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Some possible improvements, for any similar code:

  • For const LineSplitter().convert(...), one can just use LineSplitter.split(...).
  • It's easier to just match the numbers, and then work on allMatches, than to try to remove what's not numbers:
    final List<int> _transparentImage = RegExp(r'0x([A-F0-9]{2})').allMatches(_imageBytesAsString)
        .map((b) => int.parse(b[1], radix: 16))
        .toList();

.convert(_imageBytesAsString.replaceAllMapped(
RegExp(r' *0x([A-F0-9]{2}),? *\n? *'), (Match m) => '${m[1]}\n'))
.map<int>((String b) => int.parse(b, radix: 16))
.toList();
];
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@lrhn lrhn Apr 19, 2024

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Another, still simpler than the original, workaround would be:

final String _imageBytesString =
  '\x89\x50\x4E\x47\x0D\x0A\x1A\x0A\x00\x00\x00\x0D\x49'
  '\x48\x44\x52\x00\x00\x00\x01\x00\x00\x00\x01\x08\x06'
  '\x00\x00\x00\x1F\x15\xC4\x89\x00\x00\x00\x0A\x49\x44'
  '\x41\x54\x78\x9C\x63\x00\x01\x00\x00\x05\x00\x01\x0D'
  '\x0A\x2D\xB4\x00\x00\x00\x00\x49\x45\x4E\x44\xAE';
final List<int> _transparentImage = [..._imageBytesString.codeUnits];

Having a full, formatted string, and parsing it using RegExp, just to get to some bytes, feels a little like overkill.


List<int> getTestImageData() {
return _transparentImage;
Expand Down