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refactor: rewire() now does 10 times the number of edges trials by default #787

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merged 1 commit into from
Jul 3, 2024

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szhorvat
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@szhorvat szhorvat commented Jul 3, 2024

Closes #775

@ntamas, can you help with this? What should I specify as the default for n? I'm pretty sure that the way I wrote n=None is not correct.

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ntamas commented Jul 3, 2024

PyArg_ParseTupleAndKeywords(args, kwds, "|nO", kwlist, &n, &mode_o) -- this function parses n as a Python integer int and saves it in a Py_ssize_t, that's why you cannot simply pass None for n right now (see here for more details). If you wanted to support None, you would need to change the format string to |OO, parse n into a PyObject* first, check whether it's None (with == Py_None) and if not, try to cast it into a Py_ssize_t with PyNumber_AsSsize_t (see here ).

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szhorvat commented Jul 3, 2024

What I want is that the effective default be 1000*ecount. What is the best way to do this? Should the formal default be None, which is then interpreted this way? If yes, I now understand how to do that and can update this PR. Let me know.

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ntamas commented Jul 3, 2024

Yes, that's the way to go, that's how I would do it in pure Python as well.

@szhorvat szhorvat marked this pull request as ready for review July 3, 2024 17:28
@szhorvat szhorvat requested a review from ntamas July 3, 2024 17:28
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szhorvat commented Jul 3, 2024

@ntamas Have another look, I used igraphmodule_PyObject_to_integer_t() instead of PyNumber_AsSsize_t. Is this okay?

@ntamas ntamas merged commit 613d39a into main Jul 3, 2024
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@ntamas ntamas deleted the fix/rewire-count branch July 3, 2024 19:33
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The default number of trials in rewire() should be proportional to the edge count
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