fix: correct span for prefix operator (#5624)

# Description

## Problem

Resolves #5523

## Summary

The span of a Prefix expression was taken from its prefixed expression
instead of from the entire expression.

## Additional Context

I'm not sure how to test this 🤔 

## Documentation\*

Check one:
- [x] No documentation needed.
- [ ] Documentation included in this PR.
- [ ] **[For Experimental Features]** Documentation to be submitted in a
separate PR.

# PR Checklist\*

- [x] I have tested the changes locally.
- [x] I have formatted the changes with [Prettier](https://prettier.io/)
and/or `cargo fmt` on default settings.

compiler/noirc_frontend/src/elaborator/expressions.rs

@@ -39,7 +39,7 @@ impl<'context> Elaborator<'context> {
         let (hir_expr, typ) = match expr.kind {
             ExpressionKind::Literal(literal) => self.elaborate_literal(literal, expr.span),
             ExpressionKind::Block(block) => self.elaborate_block(block),
-            ExpressionKind::Prefix(prefix) => return self.elaborate_prefix(*prefix),
+            ExpressionKind::Prefix(prefix) => return self.elaborate_prefix(*prefix, expr.span),
             ExpressionKind::Index(index) => self.elaborate_index(*index),
             ExpressionKind::Call(call) => self.elaborate_call(*call, expr.span),
             ExpressionKind::MethodCall(call) => self.elaborate_method_call(*call, expr.span),
@@ -225,8 +225,7 @@ impl<'context> Elaborator<'context> {
         (HirExpression::Literal(HirLiteral::FmtStr(str, fmt_str_idents)), typ)
     }
 
-    fn elaborate_prefix(&mut self, prefix: PrefixExpression) -> (ExprId, Type) {
-        let span = prefix.rhs.span;
+    fn elaborate_prefix(&mut self, prefix: PrefixExpression, span: Span) -> (ExprId, Type) {
         let (rhs, rhs_type) = self.elaborate_expression(prefix.rhs);
         let trait_id = self.interner.get_prefix_operator_trait_method(&prefix.operator);