Handle v1.div(v2) when vectors are 2D

[davepagurek]

Resolves #5821

Changes:

• Allows the divisor's z to be 0 if the dividend's z is also 0, as this is likely a 2D vector
• The above only applies when passing a vector as the divisor, as 2D vectors store z as 0; if explicitly passing number arguments or an array, it still will log an error if z is 0
  • Is this ok or should we use the same logic for all arguments?

PR Checklist

• npm run lint passes
• [Inline documentation] is included / updated
• [Unit tests] are included / updated

[limzykenneth]

The above only applies when passing a vector as the divisor, as 2D vectors store z as 0; if explicitly passing number arguments or an array, it still will log an error if z is 0

This should be fine as the other cases have the length check so we won't have the same problem as the original issue of anbiguity between 2D and 3D vector.

Can you add to the documentation as well to note this special case?

[davepagurek]

Sounds good, docs are updated now!