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trait T0<'a, A> { | ||
type O; | ||
} | ||
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struct L<T> { | ||
f: T, | ||
} | ||
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// explicitly named variants of what one would normally denote by the | ||
// unit type `()`. Why do this? So that we can differentiate them in | ||
// the diagnostic output. | ||
struct Unit1; | ||
struct Unit2; | ||
struct Unit3; | ||
struct Unit4; | ||
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impl<'a, A, T> T0<'a, A> for L<T> | ||
where | ||
T: FnMut(A) -> Unit3, | ||
{ | ||
type O = T::Output; | ||
} | ||
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trait T1: for<'r> Ty<'r> { | ||
fn m<'a, B: Ty<'a>, F>(&self, f: F) -> Unit1 | ||
where | ||
F: for<'r> T0<'r, (<Self as Ty<'r>>::V,), O = <B as Ty<'r>>::V>, | ||
{ | ||
unimplemented!(); | ||
} | ||
} | ||
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trait Ty<'a> { | ||
type V; | ||
} | ||
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fn main() { | ||
let v = Unit2.m( | ||
//~^ ERROR type mismatch | ||
//~| ERROR type mismatch | ||
L { | ||
f : |x| { drop(x); Unit4 } | ||
}); | ||
} | ||
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impl<'a> Ty<'a> for Unit2 { | ||
type V = &'a u8; | ||
} | ||
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impl T1 for Unit2 {} |
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error[E0271]: type mismatch resolving `for<'r> <L<[closure@$DIR/issue-62203-hrtb-ice.rs:42:17: 42:39]> as T0<'r, (<Unit2 as Ty<'r>>::V,)>>::O == <_ as Ty<'r>>::V` | ||
--> $DIR/issue-62203-hrtb-ice.rs:38:19 | ||
| | ||
LL | let v = Unit2.m( | ||
| ^ expected struct `Unit4`, found associated type | ||
| | ||
= note: expected type `Unit4` | ||
found type `<_ as Ty<'_>>::V` | ||
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error[E0271]: type mismatch resolving `<[closure@$DIR/issue-62203-hrtb-ice.rs:42:17: 42:39] as std::ops::FnOnce<((&u8,),)>>::Output == Unit3` | ||
--> $DIR/issue-62203-hrtb-ice.rs:38:19 | ||
| | ||
LL | let v = Unit2.m( | ||
| ^ expected struct `Unit4`, found struct `Unit3` | ||
| | ||
= note: expected type `Unit4` | ||
found type `Unit3` | ||
= note: required because of the requirements on the impl of `for<'r> T0<'r, (<Unit2 as Ty<'r>>::V,)>` for `L<[closure@$DIR/issue-62203-hrtb-ice.rs:42:17: 42:39]>` | ||
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error: aborting due to 2 previous errors | ||
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For more information about this error, try `rustc --explain E0271`. |